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Chapter 1: Q.1-1-25c (page 27)

Why can鈥檛 molecules with the following formulas exist

a) CH5 (b) C2H5N (c)C3H5Br2

Short Answer

Expert verified

Answer

The formula C3H5Br2can鈥檛 exist.

Step by step solution

01

Carbon Valency

Carbon can form four single bonds. In this case, one-carbon includes five bonds in one representation, which is impossible as carbon valency can鈥檛 exceed five.

02

Given molecule can’t exist

In other representation, carbon forms three bonds which are one bond less for its stability. The formula C3H5Br2requires that carbon exceeds four bonds or be short of two outer shell electrons.

The representation is as follows.

C3H5Br2Molecule can鈥檛 form

C3H5Br2Molecule can鈥檛 form

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Most popular questions from this chapter

Convert the following structures into skeletal drawings

(a)

Indole

Identify all nonbonding lone pairs of electrons in the following molecules, and tell what geometry you expect for each of the indicated atoms.

  1. The oxygen atom in dimethyl ether, CH3OCH3.
  2. The nitrogen atom in trimethyl amine, N(CH3)3.
  3. The phosphorus atom in phosphine, PH3.
  4. The sulfur atom in the amino acid methionine,CH3-S-CH2-CH2-CH(NH2)-COOH .

Draw a line-bond structure for propane, CH3CH2CH3. Predict the value of each bond angle, and indicate the overall shape of the molecule.

Allene (see Problem 1-47) is structurally related to carbon dioxide, . Draw a picture showing the orbitals involved in the s and p bonds of , and identify the likely hybridization of carbon.

Draw a line-bond structure for vinyl chloride,C2H3Cl, the starting material from which PVC [poly(vinyl chloride)] plastic is made
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