/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q32 E Which of the following compounds... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 10: Q32 E (page 308)

Which of the following compounds have the same oxidation level, and which have different levels?

Short Answer

Expert verified

Same oxidation level

Different oxidation level

Step by step solution

01

Oxidation level (OL)

For organic compounds, the oxidation level of the carbon is calculated by counting the number of bonds bonded to more electronegative atoms other than carbon.

02

Compound with the same oxidation level

Epoxides have single oxygen so their OL is 1, for alcohol as there is one OH group the OL is 1 whereas in the case of ketone there is a double bond between carbon and oxygen. So, its OL is 2 and for alkene, there is a double bond its OL is -2

Thus, compounds 1,2, and 4 have the same OL and 3 and 5 have different oxidation levels.

Thus, the compounds with the some OL are:

Same oxidation level

Compounds with different oxidation level:

Different oxidation level

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Alkyl halides can be reduced to alkanes by a radical reaction with tributyltinhydride, (C4H9)3SnH in the presence of light (hv). Propose aradical chain mechanism by which the reaction might occur. The initiationstep is the light-induced homolytic cleavage of the Sn-H bondto yield a tributyltin radical.

R-X+(C4H9)3SnH鈫�hvR-H+(C4H9)3SnX

Draw structures corresponding to the following IUPAC names: (b) 4-Bromo-4-ethyl-2-methylhexane.

Draw structures corresponding to the following IUPAC names: (f) 1,1-Dibromo-4-tert-butylcyclohexane.

How would you prepare the following alkyl halides from the corresponding alcohols?

How would you prepare the following compounds, starting with cyclopentene and any other reagents needed? (c) 3-Bromocyclopentene.
See all solutions

Recommended explanations on Chemistry Textbooks

Physical Chemistry

Read Explanation

Kinetics

Read Explanation

Organic Chemistry

Read Explanation

Inorganic Chemistry

Read Explanation

Making Measurements

Read Explanation

Chemical Analysis

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.