91影视

To choose the reactant to form the conjugate addition product steps which follow are as follows:

• Aldehyde and ketone carbon numbered 鈥�1鈥� and counted two carbons away from the carbonyl carbon. The double bond in the alpha, beta-unsaturated starting material is made by connecting the carbon numbers 鈥�2鈥欌�� and 鈥�3鈥� by a double bond.
• The group bonded to the 鈥�3鈥� carbon formed the alkyl lithium reagent.

2-heptanone is synthesized by reacting with the following reagent:

• but-3-en-2-one comes from forming a double bond between 2^nd and 3^rd carbon.
• Alkyl lithium reagent $\text{Li}{\left({\text{CH}}_{\text{3}}{\text{CH}}_{\text{2}}{\text{CH}}_{\text{2}}\right)}_{\text{2}}\text{Cu}$ comes from the group joining the 3^rd carbon.

Thus but-3-en-2-one reacting with $\text{Li}{\left({\text{CH}}_{\text{3}}{\text{CH}}_{\text{2}}{\text{CH}}_{\text{2}}\right)}_{\text{2}}\text{Cu}$followed by acidic workup results in the synthesis of 2-heptanone.

Synthesis of 2-heptanone

3,3-dimethylcyclohexanoneis synthesized by reacting with the following reagent:

• 3-methylcyclohex-2-enone comes from forming a double bond between 2^nd and 3^rd carbon.
• Alkyl lithium reagent $\text{Li}{\left({\text{CH}}_{\text{3}}\right)}_{\text{2}}\text{Cu}$ comes from the group joining the 3^rd carbon.

Thus reacting 3-methylcyclohex-2-enone with $\text{Li}{\left({\text{CH}}_{\text{3}}\right)}_{\text{2}}\text{Cu}$followed by acidic workup results in the synthesis of 3,3-dimethylcyclohexanone.

Synthesis of 3,3-dimethylcyclohexanone

4-tert-Butyl-3-ethylcyclohexanone is synthesized by reacting with the following reagent:

• 4-tert-Butyl-cyclohex- 2-enone comes from forming a double bond between 2^nd and 3^rd carbon.
• Alkyl lithium reagent $\text{Li}{\left({\text{CH}}_{\text{3}}{\text{CH}}_{\text{2}}\right)}_{\text{2}}\text{Cu}$comes from the group joining the 3^rd carbon.

Thus reacting with 4-tert-Butyl-cyclohex- 2-enone$\text{Li}{\left({\text{CH}}_{\text{3}}{\text{CH}}_{\text{2}}\right)}_{\text{2}}\text{Cu}$ followed by acidic workup synthesizes 4-tert-Butyl-3-ethylcyclohexanone.

Synthesis of 4-tert-Butyl-3-ethylcyclohexanone

8a-vinyloctahydronaphthalenis synthesized by reacting with the following reagent:

• 4,4a,5,6,7,8-hexahydronaphthalen-2(3H)-one comes from forming a double bond between 2^nd and 3^rd carbon.
• Alkyl lithium reagent$\text{Li}{\left({\text{CH}}_2\text{=CH}\right)}_{\text{2}}\text{Cu}$ comes from the group joining the 3^rd carbon.

Thus reacting,4a,5,6,7,8-hexahydronaphthalen-2(3H)-one with$\text{Li}{\left({\text{CH}}_2\text{=CH}\right)}_{\text{2}}\text{Cu}$ followed by acidic workup synthesizes 8a-vinyloctahydronaphthalen.

Synthes of 8a-vinyloctahydronaphthalen