91影视

A magnetic flux $\mathrm{桅}$seems to be the magnitude of magnetic field which passes through some kind of ring of area $A$. If the magnetic field lies straight towards the plane's normal, This magnetic flux was provided by

${\mathrm{桅}}_m=BA$ $\left(1\right)$

The magnetic flux, however, would be supplied by if the magnetic field forms an angular position only with planes.

localid="1648896326026" ${\mathrm{桅}}_m=BA\cos 鈦�胃$ $\left(2\right)$

While $B$denotes the magnetic field as well as $A$denotes a substring circumference. Magnetic fields of various types and sizes and inclinations are required. Because the magnetic field of localid="1648896643020" $2\mathrm{T}$is directed through into sheet, whose angle was $0^o$. So the magnitude of the flux of is $2\mathrm{T}$

${\mathrm{桅}}_1=\left(2\mathrm{T}\right)\left(0.20\mathrm{m}\right)\left(0.20\mathrm{m}\right)\cos 鈦�\left(0^{鈭�}\right)=8脳{10}^{鈭�2}\mathrm{T}鈰�{\mathrm{m}}^2$

Since localid="1648896885167" $1\mathrm{T}$'s magnetic field is beyond the sheet, whose inclination is${180}^{鈭�}$

${\mathrm{桅}}_2=\left(1\mathrm{T}\right)\left(0.20\mathrm{m}\right)\left(0.20\mathrm{m}\right)\cos 鈦�\left({180}^{鈭�}\right)=鈭�4脳{10}^{鈭�2}\mathrm{T}鈰�{\mathrm{m}}^2$

Since the total flux through into the looping is equal to the amount of the two fluxes, the total combined flux is

${\mathrm{桅}}_{\mathrm{net}}={\mathrm{桅}}_1+{\mathrm{桅}}_2=\left(8脳{10}^{鈭�2}\mathrm{T}鈰�{\mathrm{m}}^2\right)+\left(鈭�4脳{10}^{鈭�2}\mathrm{T}鈰�{\mathrm{m}}^2\right)$

$=4脳{10}^{鈭�2}\mathrm{T}鈰�{\mathrm{m}}^2$