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A circular loop made from a flexible, conducting wire is shrinking. Its radius as a function of time is r=r0et. The loop is perpendicular to a steady, uniform magnetic field B. Find an expression for the induced emf in the loop at time t.

Short Answer

Expert verified

At time t, the solution for the induced emf in the loop is=-2ro2Be-2t

Step by step solution

01

Step: 1 Electromagnetic field:

The electromagnetic effect on moving electric charges, electromagnetic fields, and magnetic materials is represented by a magnetic field, which is a vector field. In a magnetic flux, a moving charge generates a force that is perpendicular to both its own velocity and the magnetosphere.

From Faraday's law,

=dm.

02

Step: 2 Amount of Magnetic field

Where mis the flux through the loop which is the amount of magnetic field that flows through a loop of area localid="1648957060866" Aand it is given by

m=BA

Let us use this expression of localid="1648957068013" minto equation to get

=d(BA)dt=BdAdt.

03

Step: 3 Induced emf:

The radius of the loop rchanges with time and we are given it in terms of time in the form

r=roe-t

The area of the circular loop is calculated by

A=r2=roe-t2=ro2e-2t

Now, we use the expression of Ainto equation and differentiate this equation to get the emf by

=BdAdt=Bddtro2e-2t==Bro2(-2)e-2t=-2ro2Be-2t.

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