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Chapter 12: Q35e E (page 385)

Question: At what approximate positions might the following compounds showIR absorptions?

(e)

Short Answer

Expert verified

(e) Absorption of ketone next to aromatic ring at 1690, and aromatic ring at 3030.

Step by step solution

01

Step-by-step SolutionStep 1:IR absorption

In general, IR absorption iscaused by the interaction between the IR electric field vector and molecular dipole transition related to the molecular vibrations. Absorption is at maximum when the electric field vector and dipole transition moment are parallel to each other.

02

Identify the functional group

Functional groups are groups of one or more atoms with distinctive chemical properties regardless of what is attached to them.

The atoms of the functional group are bound by covalent bonds with one another and with rest of the molecule.

The functional group in compound (e) areketone (C=O) next to aromatic ring

03

Position at which compound show IR absorptions

Given compound

(e) Absorption of ester at 1735, ketone next to aromatic ring at 1690, and aromatic ring at 3030.

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Most popular questions from this chapter

Question: Halogenated compounds are particularly easy to identify by their mass

spectra because both chlorine and bromine occur naturally as mixtures

of two abundant isotopes. Recall that chlorine occurs as 35Cl (75.8%)

and 37C (24.2%); and bromine occurs as 79Br (50.7%) and 81Br (49.3%).

At what masses do the molecular ions occur for the following formulas?

What are the relative percentages of each molecular ion?

(a)Bromomethane, CH3Br

(b)1-Chlorohexane, C6H13Cl


Draw the structure of an alkene that yields only acetone, (CH3)2C=O, on ozonolysis followed by treatment with Zn.

Question: How could you use infrared spectroscopy to distinguish between the

following pairs of isomers?

(a)HC鈮�CCH2NH2andCH3CH2C鈮�N

(b)CH3COCH3andCH3CH2CHO

Which of the following bases could be used to deprotonate 1-butyne?

(a) KOH

Question: Propose structures for compounds that fit the following mass-spectral data:

(a) A hydrocarbon with M+=132

(b) A hydrocarbon with M+=166

(c) A hydrocarbon with M+=84
See all solutions

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