91Ó°ÊÓ

It is a nucleophilic substitution reaction in which an old bond is broken and new bond is formed both processes occur simultaneously. Hence, it’s a single-step reaction.

The two reacting species are involved in the rate determining steps.

$C{H}_{3}Br\text{ }+{\text{ }}^{−}O−C{\left(C{H}_3\right)}_3\text{ }→\text{ }C{H}_3−O−C{\left(C{H}_3\right)}_3\text{ }+\text{ }NaBr$

Substitution reaction

It is a nucleophilic elimination reaction in which an old bond is broken and new bond is formed both the process occur simultaneously and no intermediate is formed.

Here, the carbon-hydrogen or halogen bond breaks to form a new double bond. Hence, it’s a single-step reaction.

$C{H}_{3}OH\text{ }+\text{ }Cl−C{\left(C{H}_3\right)}_3\text{ }→\text{ }C{H}_3−O−C{\left(C{H}_3\right)}_3\text{ }+\text{ }{\left(C{H}_3\right)}_{3}C=C{H}_2$

Elimination reaction

Here, the nucleophilic substitution occur where NaBr is produced and desired product is formed.

The two reacting species are involved in the rate determining steps.

$C{H}_{3}Br\text{ }+{\text{ }}^{−}O−C{\left(C{H}_3\right)}_3\text{ }→\text{ }C{H}_3−O−C{\left(C{H}_3\right)}_3\text{ }+\text{ }NaBr$

Substitution reaction