/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q12P-d Rank the substituents in each of... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Rank the substituents in each of the following sets according to the sequence rules:

-CH2CH3,-C≡CH,-C≡N,-CH2OCH3

Short Answer

Expert verified

Higher to lower ranking:-CH2OCH3>-C≡N>-C≡CH>-CH2CH3

Step by step solution

01

E and Z designation

Disubstituted alkenes with two substituents other than hydrogen on the double bond are only named using the cis-trans system. But when trisubstituted and tetra substitution of the double bond is present then the E and Z system is used for describing alkene stereochemistry.

02

Rule for ranking substituents

  • Consider each of the double-bond carbons separately and ranks the two substituents according to the atomic number of the first atom in each. An atom with a higher atomic number will rank higher.
  • If the first atom same then, look at the second, third, or fourth atoms away from the double-bond until the first difference is found.
  • Multiple-bonded atoms are equivalent to the same number of single-bonded atoms.
03

Ranking of given groups

As ranking is atomic number dependent, more the atomic number higher will be ranking. So,

  • In-CH2OCH3 carbon is attached two hydrogens and one oxygen.
  • In -C≡Ncarbon is attached to three nitrogen.
  • In carbon-C≡CH is attached to three carbon.
  • In carbon-CH2CH3 is attached to two hydrogens and one carbon.

So, higher to lower-ranking:-CH2OCH3>-C≡N>-C≡CH>-CH2CH3

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.