/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q36. Question:聽What is the major eno... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 23: Q36. (page 924)

Question:What is the major enolate (or carbanion) formed when each compound is treated with LDA?

Short Answer

Expert verified

Answer

The major enolate (or carbanion) formed when each compound is treated with LDA is shown below:-

Step by step solution

01

LDA (Lithium Diisopropyl Amide)

LDA is a non-nucleophilic strong base that abstracts the protons from the least hindered side.Nitrogen is attached with two bulky isopropyl groups, and due to this, it abstracts protons from the less crowded site.

02

 Step 2: The least hindered site in the given molecules

The least hindered sites in each molecule are shown below:

03

The product formed in the given reactions

Considering the key steps, the major enolate (or carbanion) formed when each compound is treated with LDA is shown below:-

Reaction a

Reaction b

Reaction c

Reaction d

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Question: Treatment of W with CH3Li, followed by CH3l, affords compound Y (C7H14O ) as the major product. Y shows a strong absorption in its IR spectrum at , and its 1 H NMR spectrum is given below. (a) Propose a structure for Y. (b) Draw a stepwise mechanism for the conversion of W to Y.

Question: The cis ketone A is isomerized to a trans ketone B with aqueous NaOH. A similar isomerization does not occur with ketone C. (a) Draw the structure of B using a chair cyclohexane. (b) Label the substituents in C as cis or trans, and explain the difference in reactivity.

Question: Draw enol tautomer(s) for each compound. Ignore stereoisomers.

Question: Draw a stepwise mechanism showing how two alkylation products are formed in the following reaction.

Question:Which of the following compounds will readily lose CO2when heated?
See all solutions

Recommended explanations on Chemistry Textbooks

Ionic and Molecular Compounds

Read Explanation

Nuclear Chemistry

Read Explanation

Physical Chemistry

Read Explanation

Chemical Analysis

Read Explanation

Chemical Reactions

Read Explanation

Organic Chemistry

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.