Chapter 10: Q.17. (page 402)
Question: Treatment of 3-methylcyclohexene with HCl yields two products, 1-chloro-3-methylcyclohexane and 1-chloro-1-methylcyclohexane. Draw a mechanism to explain this result.
Short Answer
Answer

Mechanism
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Chapter 10: Q.17. (page 402)
Question: Treatment of 3-methylcyclohexene with HCl yields two products, 1-chloro-3-methylcyclohexane and 1-chloro-1-methylcyclohexane. Draw a mechanism to explain this result.
Answer

Mechanism
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Question: When buta-1,3-diene (CH2=CH-CH=CH2) is treated with HBr, two constitutional isomers are formed CH3CHBr-CH=CH2and Br-CH2CH=CHCH2. Draw a stepwise mechanism that accounts for the formation of both products.
Question: Draw the constitutional isomer formed in each reaction.
a.

b.

c.

d.

e.

f.

Question: Lactones, cyclic esters such as compound A, are prepared by halolactonization, an addition reaction to an alkene. For example, iodolactonization of B forms lactone C, a key intermediate in the synthesis of prostaglandin (Section 4.15). Draw a stepwise mechanism for this addition reaction.

Question: a. What product(s) are formed when the E isomer of C6H5CH=CHC6H5is treated with Br2 , followed by one equivalent of KOH? Label the resulting alkene(s) as E or Z. b. What product(s) are formed when the Z isomer of C6H5CH=CHC6H5 is subjected to the same reaction sequence? c. How are the compounds in parts (a) and (b) related to each other?
Question: Draw a stepwise mechanism for the conversion of hex-5-en-1-ol to the cyclic ether A.

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