/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 34 || A 10 m×14 m house is built o... [FREE SOLUTION] | 91Ó°ÊÓ

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|| A 10 m×14 m house is built on a 12-cm-thick concrete slab.

What is the heat-loss rate through the slab if the ground temperature

is 5°C while the interior of the house is 22°C?

Short Answer

Expert verified

The power needed is 15.9 kW

Step by step solution

01

Formula to use in this problem

For thermal conduction,

dQdt=kAL∆T,

where dQ is the heat transferred in dt and dt is the time differential. If the time difference is unit,P=dQdt

02

Rearrangement of the equation and finding of the power needed

As our surface is rectangular, A=ab, where a and b are the dimensions of the floor. So,

P=kab∆TL=0.8·10·14·(22-5)0.12=1.59·104=15.9kW

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