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Chapter 19: Q. 34 (page 544)

|| A 10 m脳14 m house is built on a 12-cm-thick concrete slab.

What is the heat-loss rate through the slab if the ground temperature

is 5掳C while the interior of the house is 22掳C?

Short Answer

Expert verified

The power needed is 15.9 kW

Step by step solution

01

Formula to use in this problem

For thermal conduction,

dQdt=kAL鈭�T,

where dQ is the heat transferred in dt and dt is the time differential. If the time difference is unit,P=dQdt

02

Rearrangement of the equation and finding of the power needed

As our surface is rectangular, A=ab, where a and b are the dimensions of the floor. So,

P=kab鈭�TL=0.8路10路14路(22-5)0.12=1.59路104=15.9kW

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