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Chapter 29: Q. 25 (page 831)

Magnetic resonance imaging needs a magnetic field strength of 1.5T. The solenoid is 1.8mlong and 75cmin diameter. It is tightly wound with a single layer of 2.0mmdiameter superconducting wire. What size current is needed?

Short Answer

Expert verified

The current needed is2.4脳103A.

Step by step solution

01

Given information

We have given,

Magnetic field strength =1.5T

Length = 1.8m

Diameter = 75cm

We have to find the current through the solenoid.

02

Simplify

We know the magnetic field which is produced by uniform shape solenoid at its center.

The magnetic field is

B=渭0NIL

where N is the no. of turns and L is the length of the solenoid.

N=1.8m0.002m=900turns

Then current will be,

i=B.L渭0NI=1.5T脳1.8m4蟺脳10-7脳900I=2.4脳103A

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