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Chapter 29: Q. 61 (page 833)

An antiproton (same properties as a proton except that q=-e) is moving in the combined electric and magnetic fields of FIGURE. What are the magnitude and direction of the antiproton鈥檚 acceleration at this instant?

Short Answer

Expert verified

Acceleration,a=2.4脳1010m/s2upward

Step by step solution

01

Magnetic attraction (part a)

Due to the electrical field E, the electrical force FEis exerted on the charge, and it's given by

FE=qE

Because antiproton charge is negative, the electrical field exerts an electrical force during a downward direction.

Equation of magnetic attraction,

FB=qvB

02

Magnetic attraction (part b)

The magnetism is exerted upward within the wrong way of the electrical field force, In keeping with the right hand rule. As a result, the antiproton is subjected to the web force of the 2forces.

Fnet=FB-FE

ma=qvB-qE

a=q(vB-E)m

03

Finalization

Put the values in equation

a=q(vB-E)m

=1.6脳10-19C((500m/s)(2.5T)-1000V/m)1.67脳10-27kg

=2.4脳1010m/s2

The antiproton goes within the direction of the magnetic pull because the acceleration is positive. As a result, the acceleration is upward.

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