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Chapter 29: Q. 34 (page 832)

The two10cmlong parallel wires in FIGURE EX29.34 are separated by 5.0mm. For what value of the resistor R will the force between the two wires be 5.4脳10-5N?

Short Answer

Expert verified

The value of R is3鈩�.

Step by step solution

01

Given information

We have given,

Length of the wire =10cm

Separation between the wire = 5mm

Force =5.4脳10-5N

We have to find the resistance R as shown in the figure.

02

Simplify

We know the force between two parallel current carrying wire is

F=渭0I1I22蟺诲L

using ohm's law in the left circuit,

we can write,

I1R1=V1I1=V1R1=9V2鈩�=4.5A

Now substitute the all values that is given in this formula.

F=5.4脳10-5N=(4蟺脳10-7)脳4.5A脳I22蟺脳0.005I2=3A

Now using the ohm law in right loop, we can write,

R2=V2I2R2=9V3A=3鈩�

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