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A heat engine does10Jof work and exhausts15Jof waste heat during each cycle.

a. What is the engine's thermal efficiency?

b. If the cold-reservoir temperature is 20°C, what is the minimum possible temperature in C∘of the hot reservoir?

Short Answer

Expert verified

a.Engine thermal efficiency is40%.

b.The minimum temperature of the heat reservoir Th,minis215°C.

Step by step solution

01

Calculation for engine thermal efficiency (part a)

a.

The efficiency of a heat engine,

η=WQh

W is work done ,ηis efficiency andQhis heat used up by machine.

Qh=W+Qc

Qc is heat dumped to cold reservoir.

So, we can write our expression for the efficiency as.

η=WW+Qc

η=1010+15=40%

02

Calculation for the minimum temperature of the heat reservoir  (part b)

b.

The maximum efficiency of a Carnot engine is calculated as a function of the minimum and maximum temperatures as follows:

ηm=1-TcTh

The actual efficiency is calculated as a function of the amount of work done and the amount of heat lost.

η=WW+Qc

We can write since our engine's efficiency cannot be higher than Carnot's,

η≤ηm

WW+Qc≤1-TcTh

TcTh≤1-WW+Qc=QcW+Qc

The temperature of the heat reservoir,

Th≥W+QcQcTc

Th≥10+1515·(20+273)=488K

Th,min=215°C

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