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To calculate the coefficient of performance, we must first determine the quantity of warmth extracted from the cold reservoir and therefore the amount of labor required to get rid of it. In isochoric pressurizing, heat is removed, and therefore the gas performs positive add adiabatic expansion and negative add adiabatic compression.

The heat evacuated will be estimated as follows:

$Q_c=n{C}_v螖T$

The ideal gas law, which applies at $-23掳\mathrm{C}$, will be wont to calculate the amount of moles.

$$\begin{gathered} n=\frac{pV}{RT} \\ =\frac{1.5脳{10}^5脳1脳{10}^{-4}}{8.314脳250} \end{gathered}$$

$=7.22脳{10}^{-3}$

The heat cooled is calculated as,

$$\begin{gathered} Q_c=0.00722脳12.5脳50 \\ =4.51\mathrm{J} \end{gathered}$$

The system's work are going to be evaluated.

$W=n{C}_v螖T$

This means we'll should work out what the temperature is at the graph's other two edges. Please detain mind that in an natural process.

$T{V}^{纬-1}=const$

This implies that we will are going to be ready to locate,

$T^{\text{'}}={\left(V/V^{\text{'}}\right)}^{纬-1}T$

$V/V\text{'}$are going to be $2.5$in our example, and $纬-1=0.40$. This enables us to see $361K$and $289K$temperatures. We will now locate the network as follows:$$\begin{gathered} W=0.00722脳12.5脳\left[\right(361-250)-(289-200\left)\right] \\ =1.99\mathrm{J} \end{gathered}$$

The coefficient of performance is calculated by dividing the number of energy a system produces by the quantity of energy you place into it.

This formula for calculating performance coefficients is applicable to all or any fields.

The coefficient of performance is going to be,

$$\begin{gathered} K=\frac{Q_c}{W} \\ =\frac{4.51}{1.99} \\ =2.27 \end{gathered}$$

The power is,

$$\begin{gathered} P=Wf \\ =1.99脳60 \\ =119W \end{gathered}$$