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How much heat is exhausted to the cold reservoir by the heat engine shown in FIGUREEX21.16?


Short Answer

Expert verified

The heat exhausted to the cold reservoir by heat engine,Qc=285J.

Step by step solution

01

Step: 1 Definition of heat transfer in cold reservoirs:

(a) Heat moves spontaneously from a hot to a cold item, according to the second rule of thermodynamics.

(b) A heat engine, shown as a circle, operates by utilising some of the heat transmission. The hot and cold things are the heat and cold reservoirs.

02

Step: 2 Finding the value of Qh:

We can find the lost heat as

Qh=W+Qc⇒Qc=Qh−W

Heat taken from the heat reservoir,Qh,will be equal tothe sum of the heat taken in the two processes.That is,

Qh=90+225=315J.

03

Step: 3 Finding the value of Qc:

The work finish on the gas will be same to the space encircled by the graph. Since this is the triangle, we have

W=12⋅(300−100)⋅103⋅(600−300)⋅10−6W=30J.

Finally, the heat lost to the cold reservoir is

Qc=315−30Qc=285J.

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