/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 15 What are (a) the thermal efficie... [FREE SOLUTION] | 91影视

91影视

What are (a) the thermal efficiency and (b) the heat extracted from the hot reservoir for the heat engine shown in FIGUREEX21.15?

Short Answer

Expert verified

a.Thermal efficiency heat engine is13%.

b.The heat extracted from the hot reservoir for the heat engine is320J.

Step by step solution

01

Calculation for efficiency of heat engine (part a)

a.

To calculate the efficiency we can use the following formula,

=WoutQ=WoutWout+Qc

where Qcis the heat that was given to the cold reservoir.

On the other hand, the work done by the gas in one cycle will be equal to the region encircled by the graph.

Work is ,

localid="1648643811450" role="math" Wout=12(300-100)103(600-200)10-6=40J

On the other hand, the total amount of heat lost is equal to the sum of the two losses.

localid="1648643864648" role="math" Qc=100+180=280J

The efficiency ,

localid="1648643885687" =4040+28013%

02

Calculation for the heat extracted from the hot reservoir for the heat engine (part b)

b.

The heat extracted from the hot reservoir will be as follows:

From solution a,

Wout=40J

Qc=280

Substitute above value,

we get,

Qc=Wout+Qc=40+280=320J

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A heat engine running backward is called a refrigerator if its purpose is to extract heat from a cold reservoir. The same engine running backward is called a heat pump if its purpose is to exhaust warm air into the hot reservoir. Heat pumps are widely used for home heating. You can think of a heat pump as a refrigerator that is cooling the already cold outdoors and, with its exhaust heat QH, warming the indoors. Perhaps this seems a little silly, but consider the following. Electricity can be directly used to heat a home by passing an electric current through a heating coil. This is a direct, 100%conversion of work to heat. That is, 15kWof electric power (generated by doing work at the rate of 15kJ/sat the power plant) produces heat energy inside the home at a rate of 15kJ/s. Suppose that the neighbor鈥檚 home has a heat pump with a coefficient of performance of 5.0, a realistic value. Note that 鈥渨hat you get鈥 with a heat pump is heat delivered, QH, so a heat pump鈥檚 coefficient of performance is defined asK=QH/Win.

a. How much electric power inkWdoes the heat pump use to deliver 15kJ/sof heat energy to the house?

b. An average price for electricity is about 40MJper dollar. A furnace or heat pump will run typically 250 hours per month during the winter. What does one month鈥檚 heating cost in the home with a 15kW electric heater and in the home of the neighbor who uses a heat pump?

An ideal refrigerator utilizes a Carnot cycle operating between 0Cand 25C. To turn 10Kgof liquid water at 0Cinto 10Kgof ice at 0C,

aHow much heat is exhausted into the room and

bHow much energy must be supplied to the refrigerator?

A heat engine does10Jof work and exhausts15Jof waste heat during each cycle.

a. What is the engine's thermal efficiency?

b. If the cold-reservoir temperature is 20C, what is the minimum possible temperature in Cof the hot reservoir?

What are (a) the heat extracted from the cold reservoir and (b) the coefficient of performance for the refrigerator shown in Figure Ex-21.20?

A gas following the pVtrajectory of FIGURE EX21.12does 60Jof work per cycle. What is pmax?



See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.