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Chapter 10: Q10-25E-b (page 308)

How would you prepare the following compounds, starting with cyclopentene and any other reagents needed? (b) Methylcyclopentane.

Short Answer

Expert verified

Methylcyclopentane can be formed in the following way:

Step by step solution

01

Step-by-step solutionStep 1: Chlorination

It means substitution of one hydrogen from the reactant, so that halogen atom can be added there.

02

Alkyl halide

Alkyl halides are also known as haloalkanes or halogenoalkanes. They contains one or more halogen substituents i.e. 鈥揃r, -Cl,-I,-F.

03

Preparation of methylcyclopentane

The desired product methylcyclopentane can be prepared by brominating cyclopantene and then reducing bromocyclopantane to methylcyclopentane.

The reaction is as follows:

Preparation of methylcyclopentane

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Most popular questions from this chapter

Carboxylic acids (RCOOH; pKa=5) are approximately 1011 times more

acidic than alcohols (ROH;pKa=16). In other words, a carboxylate ion(RCO2-)

is more stable than an alkoxide ion (RO-). Explain, using

resonance.

Question: Name the following alkyl halides:

Give IUPAC names for the following alkyl halide (d):

How would you prepare the following compounds, starting with cyclopentene and any other reagents needed? (d) Cyclopentanol.

In light of the fact that tertiary alkyl halides undergo spontaneous dissociation to yield a carbocation plus halide ion (see Problem 10-45), propose a mechanism for the following reaction.
See all solutions

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