/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q4P Give the structures of both 1,2 ... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 14: Q4P (page 427)

Give the structures of both 1,2 and 1,4 adducts resulting from reaction of 1 equivalent of HBr with the following compound:

Short Answer

Expert verified

Halogen halide reacts with alkene hydrogen attached to one sp2carbon of alkene and halide added to anothersp2alkene carbon; even when the double bond is in the ring compound, the result is the same.

Hydrogen halides, e.g., HCl, HBr, or HI, react with an alkene, e.g., ethylene form alkyl halide as the product

Step by step solution

01

Addition of hydrogen halide to an alkene

Halogen halide reacts with alkene hydrogen attached to one sp2carbon of alkene and halide added to anothersp2alkene carbon; even when the double bond is in the ring compound, the result is the same.

Hydrogen halides, e.g., HCl, HBr, or HI, react with an alkene, e.g., ethylene form alkyl halide as the product

02

Formation of 1,2 and 1,4 adducts

2,3-dimethylcyclohexa-1,3-diene having a double bond, reacts with hydrogen halide HBr to give the carbocation, which is resonance stabilized (two resonating structures).

Two carbocation forms get attacked by the nucleophile bromine ion to result in the formation of two different types of products (adducts):

  • 1,2 product is 6-bromo-1,6-dimethylcyclohex-1-ene
  • 1,4 product is 3-bromo-1,2-dimethylcyclohex-1-ene

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

If pure vitamin A has位max =5 325 (蔚= 50,100), what is the vitamin A concentration in a sample whose absorbance at 325 nm is A = 0.735 in a cell with a path length of 1.00 cm?

Arrange the molecules according to where you would expect to find

their wavelength of maximum absorption in UV spectroscopy, from shortest to longest wavelength.

a)

b)

c)

The following Diene does not undergo Diels鈥揂lder reactions. Explain.

How could you use Diels-Alder reactions to prepare the following products ? Show the starting diene and dienophile in each case.

a)

The following ultraviolet absorption maxima have been measured:

1,3-Butadiene 217 nm

2-Methyl-1,3-butadiene 220 nm

1,3-Pentadiene 223 nm

2,3-Dimethyl-1,3-butadiene 226 nm

2,4-Hexadiene227 nm

2,4-Dimethyl-1,3-pentadiene 232 nm

2,5-Dimethyl-2,4-hexadiene 240 nm

What conclusion can you draw about the effect of alkyl substitution on

UV absorption maxima? Approximately what effect does each added

alkyl group have?
See all solutions

Recommended explanations on Chemistry Textbooks

Chemical Reactions

Read Explanation

The Earths Atmosphere

Read Explanation

Physical Chemistry

Read Explanation

Organic Chemistry

Read Explanation

Chemical Analysis

Read Explanation

Making Measurements

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.