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Chapter 6: Q6-26E (page 181)

Add curved arrows to the mechanism shown in Problem 6-25 to indicate the electron movement in each step.

Short Answer

Expert verified

In the first step of the reaction蟺 bond of alkene abstract hydrogen ion. In the next step, we get the carbocation as an intermediate. In the next step hydrogen atom loss and we resultant alkene as a product.

Step by step solution

01

Movement of electron

In the first step of the reaction蟺 bond of alkene abstract hydrogen ion. In the next step, we get the carbocation as an intermediate. In the next step hydrogen atom loss and we resultant alkene as a product.

02

Mechanism of the reaction

The mechanism of the reaction is as follows:

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Most popular questions from this chapter

Add curved arrows to the following polar reactions to indicate the flow of electrons in each:

For each reaction below identify the electrophile and the nucleophile

(a)

(b)

(c)

For each alkene below, use curved arrows to show how it would react with a proton. Draw the carbocation that would form in each case.

a)

b)

c)

Follow the flow of electrons indicated by the curved arrows in each of the following polar reactions, and predict the products that result:

Which reaction is more energetically favored, one with 螖骋o= - 44 or one with 螖骋o= +44 ?
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