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Chapter 6: Problem 6.29 (page 241)

Use full-headed or half-headed curved arrows to show the movement of electrons in each reaction.

a.

b.

c.

d.

Short Answer

Expert verified

Answer

a.

b.

c.

d.

Step by step solution

01

Step-by-Step SolutionStep 1: Full-headed and Half-headed curved arrows

A full-headed arrow is used to indicate the movement/transfer of a pair of electrons.

A half-headed arrow indicates the transfer of a single electron.

02

Movement of electrons in reaction a and b

The movement of electrons in reactions a and b are as follows:

a.

Reaction a

b.Reaction b

03

Movement of electrons in reaction c and d

The movement of electrons in reactions c and dare as follows:

c.

Reaction c

d.Reaction d

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Most popular questions from this chapter

For each rate equation, what effect does the indicated concentration change have on the overall rate of the reaction?

[1] rate=k[CH3CH2Br][-OH]

  1. tripling the concentration of CH3CH2Bronly
  2. tripling the concentration of 鈥� OH only
  3. tripling the concentration of both CH3CH2Br and 鈥� OH

[2]role="math" localid="1648280223497" rate=k[(CH3)3COH]

  1. doubling the concentration of (CH3)3COH
  2. increasing the concentration of (CH3)3COH by a factor of 10

Draw the products of each reaction by following the curved arrows.

a.

b.

Given each value, determine whether the starting material or the product is favored at equilibrium.

a.Keq=0.5

b.鈭�G掳=-100kJ/mol

c.鈭�H掳=8.0kJ/mol

d. Keq=16

e.鈭�G掳=-2.0kJ/mol

f.鈭�H掳=200kJ/mol

g.鈭�S掳=8J/(K.mol)

h.鈭�S掳=-8J/(K.mol)

Given each of the following values, is the starting material or product favored at equilibrium?

a.Keq=5.5

b.螖骋掳=40kJ/mol

Indicate which factors affect the rate of a reaction.

  1. 鈭�G掳
  2. 鈭�H掳
  3. Ea
  4. Temperature
  5. concentration
  6. width="28">Keq
  7. k
  8. Catalysts
See all solutions

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