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Explain why the bond dissociation energy for bond (a) is lower than the bond dissociation energy for bond (b).

Short Answer

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Answer

Bond b has higher bond dissociation energy than bond a as it is adjacent to a double bond.

Step by step solution

01

Step-by-Step SolutionStep 1: Bond dissociation energy

The energy required to break a chemical bond is termed bond dissociation energy.

As the number of bonds between two atoms increases, the bond dissociation energy also increases.

02

Skeletal structures of the given compounds

The skeletal structures of the given compounds are as follows:Skeletal structure of a

Skeletal structure of b

03

Bond dissociation energy of compounds a and b

Bond b has higher dissociation energy than a as it is adjacent to a double bond, or in other words, b involves bond formation between sp2and sp hybridized carbon atoms.

In the case of bond a, both the carbon atoms involved in bonding are sp3hybridized.

As the percent s character of the atoms involved in bonding increases, the bond strength increases, and the bond dissociation energy also increases.

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Most popular questions from this chapter

Label each statement as true or false. Correct any false statement to make it true.

a. Increasing temperature increases reaction rate.

b. If a reaction is fast, it has a large rate constant.

c. A fast reaction has a large negative ∆G°value.

d. When Eais large, the rate constant k is also large.

e. Fast reactions have equilibrium constants > 1.

f. Increasing the concentration of a reactant always increases the rate of a reaction.

What carbon radical is formed by homolysis of theC-Ha bond in propylbenzene? Draw all reasonable resonance structures for this radical.

What carbon radical is formed by homolysis of therole="math" localid="1648540916945" C-Hbbond in propylbenzene? Draw all reasonable resonance structures for this radical.

The bond dissociation energy of one of the C-H bonds is considerably less than the bond dissociation energy of the other. Which C-H bond is weaker? Offer an explanation.

Calculate Δ±á° for each oxidation reaction. Each equation is balanced as written; remember to take into account the coefficients in determining the number of bonds broken or formed.

[ Δ±á∘for O2=497kJ/mol ; Δ±á∘for one C=O in CO2=535kJ/mol]

a.role="math" localid="1648191068323" CH4+2O2→CO2+2H2O

b.2CH4+7O2→4CO2+6H2O


Indicate which factors affect the rate of a reaction.

  1. ∆G°
  2. ∆H°
  3. Ea
  4. Temperature
  5. concentration
  6. width="28">Keq
  7. k
  8. Catalysts

Explain why HC≡CHis more acidic than CH3CH3, even though the C-H bond in HC≡CHhas a higher bond dissociation energy than the C-H bond in CH3CH3.

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