91Ó°ÊÓ

Isomers exhibiting an alteration in atomic arrangement but possess equivalent molecular formulas are stereoisomers.Stereoisomers can be of various kinds, and they include enantiomers and diastereomers.

The number of stereoisomers can be found by the formula as follows:

${\text{Numberofsteroeisomers=2}}^n$

Here, n is the number of chiral centers.

a. The number of chiral centers in compound a is two.

The chiral centers in the molecule a are represented as asterisk as follows:

Chiral centers in the molecule a

So, the number of stereoisomers can be given as follows:

$$\begin{gathered} {\text{Numberofstereosimers=2}}^n \\ =2^2 \\ =4 \end{gathered}$$

Hence, the maximum number of possible isomers for compound a is four.

b. The number of chiral centers in compound b is zero.

Hence, the given compound cannot form stereoisomers.

c. The number of chiral centers in compound c is four.

The chiral centers in molecule c can be represented as asterisk as follows:

Chiral centers in the molecule c

So the number of stereoisomers in compound c can be given as follows:

$$\begin{gathered} {\text{Numberofstereosimers=2}}^n \\ =2^4 \\ =16 \end{gathered}$$

Hence, the maximum number of possible isomers for compound c is 16.