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Chapter 5: Q.30 (page 200)

What is the ee for each of the following mixtures of enantiomers A and B?

a. 95% A and 5% B

b. 85% A and 15% B

Short Answer

Expert verified

a. The ee is 90%.

b. The ee is 70%.

Step by step solution

01

Enantiomeric excess (ee)

The enantiomeric excess determines the excess amount of any one of the enantiomers (either R or S). It is also termed an optically pure compound.

02

Formula to calculate the ee

The formula to calculate the ee is as follows:

ee=%ofoneenantiomer-%ofotherenantiomer.

03

Explanation

a. The ee is calculated from the A and B as:

ee=95%-5%=5%

Therefore, the ee for enantiomers is 90%.

b. The ee is calculated from the A and B as:

ee=85%-15%=70%

Therefore, the ee for enantiomers is 70%.

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Most popular questions from this chapter

a. Locate all the tetrahedral stereogenic centers in discodermolide, a tumor inhibitor isolated from the Caribbean marine sponge Discodermiadissoluta.

b. Certain carbon鈥揷arbon double bonds can also be stereogenic centers. With reference to the definition in Section 5.3, explain how this can occur, and then locate the three additional stereogenic centers in discodermolide.

c. Considering all stereogenic centers, what is the maximum number of stereoisomers possible for discodermolide?

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