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Chapter 5: Q.30 (page 200)

What is the ee for each of the following mixtures of enantiomers A and B?

a. 95% A and 5% B

b. 85% A and 15% B

Short Answer

Expert verified

a. The ee is 90%.

b. The ee is 70%.

Step by step solution

01

Enantiomeric excess (ee)

The enantiomeric excess determines the excess amount of any one of the enantiomers (either R or S). It is also termed an optically pure compound.

02

Formula to calculate the ee

The formula to calculate the ee is as follows:

ee=%ofoneenantiomer-%ofotherenantiomer.

03

Explanation

a. The ee is calculated from the A and B as:

ee=95%-5%=5%

Therefore, the ee for enantiomers is 90%.

b. The ee is calculated from the A and B as:

ee=85%-15%=70%

Therefore, the ee for enantiomers is 70%.

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Most popular questions from this chapter

Locate the stereogenic centers in each compound. A molecule may have zero, one, or more stereogenic centers. Gabapentin [part (d)] is used clinically to treat seizures and certain types of chronic pain. Gabapentin enacarbil [part (e)] is a related compound that is three times more potent.

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Like carvone, the two enantiomers of celery ketone smell differently. The R enantiomer smells like celery leaves, whereas the S enantiomer smells like licorice. Draw each enantiomer and assign its odor.

a) Locate the stereogenic centers in the ball-and-stick model of ezetimibe (trade name Zetia), a cholesterol-lowering drug. (b) Label each stereogenic center as R or S.

Locate the stereogenic centers in each compound.

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Label the two stereogenic centers in each compound and draw all possible stereoisomers.

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