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Chapter 15: Q6. (page 570)

Question: Using Mechanism 15.1 as a guide, write the mechanism for the reaction of CH4with Br2 to form CH3 Br and HBr. Classify each step as initiation, propagation, or termination.

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01

Radical halogenation of alkanes

The first step is initiation that involves the hemolysis cleavage ofform two radicals.


The second step is propagation that involves the attack of the radical to the alkane to form alkyl and radical.


The third step is termination that involves the reaction of radicals together to stop the chain.

02

 Step 2: Explanation

The steps involved in the reaction are shown below:

Initiation:

Initiation reaction

Propagation:

Propagation reaction

Termination:

Termination reaction

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Most popular questions from this chapter

Question: With reference to the indicated C-H bonds in 2-methylbutane.

a. Rank the C-H bonds in order of increasing bond length.

b. Draw the radical resulting from cleavage of each C-H bond and classify it as 10,20, or 30

c.Rank the order of radicals in order of increasing stability.

Rank the C-H bonds in order of increasing ease of H abstractions in a radical halogenation reaction.

Question: What alkane is needed to make each alkyl halide by radical halogenation?

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This reaction has been employed in many radical cyclization reactions. Draw a stepwise mechanism for the following reaction.

Question: Although CH4 reacts with Cl2 to form CH3Cl and HCl, the corresponding reaction of CH4with l2does not occur at an appreciable rate, even though the bond is much weaker than the bond. Explain why this is so.
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