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Chapter 15: Q38. (page 570)

Question: Which alkyl halides can be prepared in good yield by radical halogenation of an alkane?

Short Answer

Expert verified

Answer

The tertiary alkyl halide (a) would be prepared in good yield by radical halogenation of an alkane.

Step by step solution

01

Radical halogenation

The organic reaction involving the substitution of the most reactive hydrogen atom in an alkane by a halide ion, namely chloride ion or bromide ion to form the corresponding alkyl halide is known as the radical halogenation reaction.

02

Predominance of alkyl halide

The relative stability of carbocations is as follows,

Tertiary > Secondary > Primary

Among the given set of alkyl halides, the one with the halide ion bonded to a tertiary carbon atom would be prepared in good yield.

a.

Therefore, compound (a) is prepared in good yield.

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Most popular questions from this chapter

Questions: Compounds A and B are isomers having molecular formula C5H12. Heating A with Cl2 gives a single product of monohalogenation, whereas heating B under the same conditions forms three constitutional isomers. What are the structures of A and B?

Question: Draw the product(s) formed when each alkene is treated with either [1] HBr alone; or [2] HBr in the presence of peroxides.

a.

b.

c.

Question: Draw the organic products formed in each reaction.

a.

b.

c.

d.

e.

f.

Question: As we will learn in Chapter 30, styrene derivatives such as A can be polymerized by way of cationic rather than radical intermediates. Cationic polymerization is an example of electrophilic addition to an alkene involving carbocations.

a. Draw a short segment of the polymer formed by the polymerization of A.

b. Why does A react faster than styrene (C6H5CH=CH2)in a cationic polymerization?

Question: Draw all resonance structures of the radical that results from abstraction of a hydrogen atom from the antioxidant BHA (butylated hydroxy anisole).
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