Chapter 14: Q.21558-14-43P (page 563)
Question: How can you use 1H NMR spectroscopy to distinguish between CH2=C(Br)CO2CH3 and methyl (E)-3-bromopropenoate, BrCH=CHCO2CH3?
Short Answer
Answer

/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none}
Learning Materials
Features
Discover
Chapter 14: Q.21558-14-43P (page 563)
Question: How can you use 1H NMR spectroscopy to distinguish between CH2=C(Br)CO2CH3 and methyl (E)-3-bromopropenoate, BrCH=CHCO2CH3?
Answer

All the tools & learning materials you need for study success - in one app.
Get started for free
Question. Treatment of (CH3)2 CHCH2CH(OH)CH2CH3 with TsOH affords two products (M and N) with the molecular formula C6H12 . The 1 H NMR spectra of M and N are given below. Propose structures for M and N, and draw a mechanism to explain their formation.

Into how many peaks will each proton shown in green be split?
a.

b.

c.

d.

e.

f.

Question. Reaction of aldehyde D with amino alcohol E in the presence of NaH forms F (molecular formula C11H15NO2). F absorbs at 1730 cm-1in its IR spectrum. F also shows eight lines in its 13C-NMR spectrum, and gives the following -NMR spectrum: 2.32 (singlet, 6 H), 3.05 (triplet, 2 H), 4.20 (triplet, 2 H), 6.97 (doublet, 2 H), 7.82 (doublet, 2 H), and 9.97 (singlet, 1 H) ppm. Propose a structure for F. We will learn about this reaction in Chapter 18.
Which of the highlighted carbon atoms in each molecule absorbs farther downfield?
a.

b.

c.

d.

Question: How many 1H NMR signals does each natural product exhibit?
a.

b.

c.

d.

What do you think about this solution?
We value your feedback to improve our textbook solutions.