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Question: Rank each group of protons in order of increasing chemical shift.

a.

b.

Short Answer

Expert verified

a. \({{\rm{H}}_{\rm{c}}}\;\langle \;{{\rm{H}}_{\rm{a}}}\;\langle \;{{\rm{H}}_{\rm{b}}}\)

b.\({{\rm{H}}_{\rm{c}}}\;\langle \;{{\rm{H}}_{\rm{a}}}\;\langle \;{{\rm{H}}_{\rm{b}}}\)

Step by step solution

01

Chemical shift

The difference in the absorption position of a particular proton due to variation in its chemical environment from that of an isolated proton is the chemical shift of that proton.It is usually represented by\(\delta \)-scale and \(\tau \)-scale.

02

Equation for chemical shift

A chemical shift in terms of frequency can be represented by the equation:

\(\delta = \frac{{{\nu _{sample}} - {\nu _{reference}}}}{{{\nu _{sample}}}} \times {10^6}\)

03

Ranking each group of protons in order of increasing chemical shift

Representation of different protons in a.

Since \({{\rm{H}}_{\rm{c}}}\)is bonded to the \({\rm{s}}{{\rm{p}}^{\rm{3}}}\;{\rm{C}}\)\({{\rm{H}}_{\rm{c}}}\), the protons are highly shielded, and this gives them the lowest chemical shift value. \({{\rm{H}}_{\rm{a}}}\;\)is bonded to an \({\rm{sp}}\;{\rm{C}}\), so they are shielded, giving them a chemical shift value higher than that of \({{\rm{H}}_{\rm{c}}}\). And the \({{\rm{H}}_{\rm{b}}}\)protons are deshielded as they are bonded to the \({\rm{s}}{{\rm{p}}^{\rm{2}}}\;{\rm{C}}\), which gives them a higher chemical shift value. So, the order of increasing chemical shift value is, \({{\rm{H}}_{\rm{c}}}\;\langle \;{{\rm{H}}_{\rm{a}}}\;\langle \;{{\rm{H}}_{\rm{b}}}\).

Representation of different protons in b.

Since \({{\rm{H}}_{\rm{c}}}\)is bonded to the \({\rm{s}}{{\rm{p}}^{\rm{3}}}\;{\rm{C}}\)\({{\rm{H}}_{\rm{c}}}\) , the protons are highly shielded and this gives them the lowest chemical shift value. \({{\rm{H}}_{\rm{a}}}\;\)is slightly deshielded as the \({\rm{C}}{{\rm{H}}_3}\) group is bonded to a C=O, and this gives them a chemical shift value higher than that of \({{\rm{H}}_{\rm{c}}}\). And the \({{\rm{H}}_{\rm{b}}}\)protons are deshielded as the \({\rm{C}}{{\rm{H}}_2}\)group is bonded to an O atom, which gives them a higher chemical shift value. So, the order of increasing chemical shift value is,\({{\rm{H}}_{\rm{c}}}\;\langle \;{{\rm{H}}_{\rm{a}}}\;\langle \;{{\rm{H}}_{\rm{b}}}\).

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Most popular questions from this chapter

Question:Propose a structure consistent with each set of spectral data:

a. C4H8Br2: IR peak at 3000–2850cm-1 ;

NMR (ppm):

1.87 (singlet, 6 H)

3.86 (singlet, 2 H)

b. C3H6Br2: IR peak at 3000–2850cm-1 ;

NMR (ppm):

2.4 (quintet)

3.5 (triplet)

c. C5H10O2: IR peak at 1740cm-1 ;

NMR (ppm):

1.15 (triplet, 3 H) 2.30 (quartet, 2 H)

1.25 (triplet, 3 H) 4.72 (quartet, 2 H)

d . C6H14O: IR peak at 3600-3200 cm-1 ;

NMR (ppm):

0.8 (triplet, 6 H) 1.5 (quartet, 4 H)

1.0 (singlet, 3 H) 1.6 (singlet, 1 H)

e. C6H14O: IR peak at 3000-2850cm-1 ;

NMR (ppm):

1.10 (doublet, relative area = 6)

3.60 (septet, relative area = 1)

f . C3H6O: IR peak at 1730cm-1 ;

NMR (ppm):

1.11 (triplet)

2.46 (multiplet)

9.79 (triplet)

Draw all constitutional isomers of molecular formula \({{\bf{C}}_{\bf{3}}}{{\bf{H}}_{\bf{6}}}{\bf{C}}{{\bf{l}}_{\bf{2}}}\).

a. How many signals does each isomer exhibit in its \({}^{\bf{1}}{\bf{H}}\) NMR spectrum?

b. How many lines does each isomer exhibit in its \({}^{{\bf{13}}}{\bf{C}}\) NMR spectrum?

c. When only the number of signals in both \({}^{\bf{1}}{\bf{H}}\) and \({}^{{\bf{13}}}{\bf{C}}\) NMR spectroscopy is considered, is it possible to distinguish all of these constitutional isomers?

Question: Draw the four constitutional isomers having molecular formula C4H9Brand indicate how many different kinds of carbon atoms each has.

Question: Identify the structures of isomers H and I (molecular form C8H11N)

a.

b.

Question: The 1 H NMR spectrum of N,N-dimethylformamide shows three singlets at 2.9, 3.0, and 8.0 ppm. Explain why the two groups are not equivalent to each other, thus giving rise to two NMR signals.

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