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Chapter 29: Question 30.30 (page 1152)

Draw each polymer in Problem 30.29 using the shorthand representation shown in Figure 30.2.

Short Answer

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Answer

Step by step solution

01

Polymer

Polymers are formed by the addition/condensation of monomer units that form large/long-chain molecules.Polymers are also said to be macromolecules i.e. higher molecular mass.

02

Structure of polymer

In the above question, there are 4 polymers in chain form. We have to represent them in shorthand form.

The monomer of this polymer is ethyl acetoacetate.

Structure of ethyl acetoacetate polymer

The monomer of this polymer is amino cyclohexane carboxylic acid.

Structure of amino cyclohexane carboxylic acid polymer

The monomer of this polymer is 2, 2-dimethyl butane carboxyl.

Structure of 2, 2-dimethyl butane carboxyl polymer

The monomer of this polymer is 1, 3-propandiol.

Structure of 1, 3-propandiol polymer

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Most popular questions from this chapter

What alkyl halide is needed to synthesize each amino acid from diethyl acetamidomalonate: (a)Asn; (b)His; (c)Trp?

Draw all the steps in the synthesis of each peptide from individual amino acids:

(a)Gly-Ala;

(b) Ile-Ala-Phe

Question: Identify the functional groups in each molecule. Classify each alcohol, alkyl halide, amide, and amine as 1掳, 2掳, or 3掳

a.

b.

c.

d.

e.

f.

Identify the lettered intermediates in the following reaction scheme. This is an alternative method to synthesize amino acids, based on the Gabriel synthesis of 1掳 amines (Section 25.7A).

The fibroin proteins found in silk fibers consist of large regions of 尾-pleated sheets stacked one on top of another. (a) Explain why having a glycine at every other residue allows the 尾-pleated sheets to stack on top of each other. (b) Why are silk fibers insoluble in water?
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