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Chapter 10: Q.26. (page 413)

Question: What alkylborane is formed from hydroboration of each alkene?

Short Answer

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Answer

Step by step solution

01

Hydroboration

In hydroboration reaction, the hydrogen-boron atom gets added with a double bond, that is, C=C or C=N.

02

Formation of products

a. The hydroboration of 2-methylprop-1-enegives isobutylborane as shown below:

Formation of product in a

b. The hydroboration of hex-1-enegives hexylborane as shown below:

Formation of product in b

c. The hydroboration of methylenecyclopentane gives (cyclopentylmethyl)borane as shown below:

Formation of product in c

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Most popular questions from this chapter

Question: Use the Hammond postulate to explain why (CH3)2C=CH2reacts faster than CH3CH=CH2 in electrophilic addition of HX.

Question: Calculate the number of degrees of unsaturation for each molecular formula.

a. C6H8

b. C40H56

c. C10H16O2

d. C8H9Br

e. C8H9ClO

f. C7H11N

g. C4H8BrN

h. C10H10ClNO

Question: What two alkenes give rise to each alcohol as the major product of acid-catalyzed hydration?

Question: Label each carbon-carbon double bond in 11-cis-retinal as E or Z. As we will learn in Section 21.11, the isomerization of one double bond in this compound to a less crowded stereoisomer takes place when light strikes the retina of the eye.

Question: Less stable alkenes can be isomerized to more stable alkenes by treatment with strong acid. For example, 2,3-dimethylbut-1-ene is converted to 2,3-dimethylbut-2-ene when treated with . Draw a stepwise mechanism for this isomerization process.
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