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Chapter 2: Q. 2.67 (page 89)

Draw the product formed when the Lewis acid (CH3CH2)3C+reacts with each Lewis base:

role="math" localid="1649304251552" (a)CH3OH;(b)(CH3)2O;(c)(CH3)2NH.

Short Answer

Expert verified

The combination of a Lewis acid with a Lewis base produces the product that is noted as a Lewis acid-base adduct.Several of the Lewis acid-base reactions come under the category of displacement reactions.

Step by step solution

01

Lewis acid-base reaction

The combination of a Lewis acid with a Lewis base produces the product that is noted as a Lewis acid-base adduct.Several of the Lewis acid-base reactions come under the category of displacement reactions.

02

Reaction of (CH3CH2)3C+ with given compounds

(a) The Lewis base CH3OHprovides the electron to the Lewis acid leading to the formation of a Lewis acid-base adduct as given below:

(b) The Lewis base (CH3)2Odonates the electron to the Lewis acid leading to the formation of a Lewis acid-base adduct, as shown below:

(c) The Lewis base(CH3)2NHcontributes its electron to the Lewis acid leading to the formation of a Lewis acid-base adduct as mentioned below:

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Most popular questions from this chapter

Draw the products formed from the acid鈥揵ase reaction of with each compound.

a.

b.

c.

d.

The pKa of three C-H bonds is given below.

a. For each compound, draw the conjugate base, including all possible resonance structures.

b. Explain the observed trend in pKa.

What isKa for each compound? Use a calculator when necessary.

a.H2SpKa=7.0

b.ClCH2COOHpKa=2.8

c.HCNpKa=9.1

What is the conjugate acid of each base?

a. HCO3-

b.

c.

d.

Which H atom in vitamin C (ascorbic acid) is most acidic?
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