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Chapter 2: 2.38 (page 85)

What is the conjugate acid of each base?
a. ${HCO}_{3}^{-}$
b.
c.
d.

Short Answer

Expert verified

a. $H_{2} {CO}_{3}$

b. role="math" localid="1649075555384" ${CH}_{3} {CH}_{2} {CH}_{2} \overset{+}{N} H_{2} {CH}_{3}$

c. ${CH}_{3} \overset{+}{O} {HCH}_{3}$

d. ${CH}_{3} COOH$

Step by step solution

01

Base

A base can abstract the acidic proton from the acid.

02

Conjugate acid

The conjugate acid is formed through the proton abstraction by a base.

03

Formation of the conjugate acid

a.The base ${HCO}_{3}^{-}$ abstracts the proton and forms its conjugate acid $H_{2} {CO}_{3}$ .

${HCO}_{3}^{-} \overset{H^{+}}{鈫�} H_{2} {CO}_{3}$

b. The base ${CH}_{3} {CH}_{2} {CH}_{2} {NHCH}_{3}$ abstracts the proton and forms its conjugate acid ${CH}_{3} {CH}_{2} {CH}_{2} \overset{+}{N} H_{2} {CH}_{3}$ .

Formation of a conjugate acid

c.The base ${CH}_{3} {OCH}_{3}$ abstracts the proton and forms its conjugate acid ${CH}_{3} \overset{+}{O} {HCH}_{3}$ .

Formation of a conjugate acid

d.The base ${CH}_{3} {COO}^{-}$ abstracts the proton and forms its conjugate acid ${CH}_{3} COOH$ .

Formation of a conjugate acid

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Most popular questions from this chapter

Answer the following questions about esmolol, a drug used to treat high blood pressure sold under the trade name Brevibloc.

a. Label the most acidic hydrogen atom

b. What products are formed when esmolol is treated with NaH?

c. What products are formed when esmolol is treated with HCl?

d. Label all ${sp}^{2}$ hybridized C atoms. in esmolol.

e. Label the only trigonal pyramidal atom.

f. Label all C鈥檚 that bear a $未^{+}$ charge.

Classify each compound as a Lewis base, a Br酶nsted -Lowry base, both or neither.

a.

b.

c.

d.

Rank the compounds in each group in order of increasing acidity.

a.

b.

c.

Which compound in each pair of isomers is the stronger acid?

a.

or

b.

or

Explain the apparent paradox. HBr is a stronger acid than HCl, but HOCl is a stronger acid than HOBr.

See all solutions

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