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A thin solid barrier in the xy-plane has a 10μmdiameter circular hole. An electron traveling in the zdirection with vx=0m/spasses through the hole. Afterward, is it certain that vxis still zero? If not, within what range is vxlikely to be?

Short Answer

Expert verified

The average velocity is zero. So, the range of velocity is from-18m/sto18m/s

Step by step solution

01

Heisenberg relation:

Heisenberg relation for position and momentum of a particle is,

∆x∆px≥h2

Rewrite the equation for ∆x,

∆px=h2∆x.....(1)

The relationship between ∆vxand ∆px

∆px=m∆vx.......(2)

02

Conversion diameter:

Convert diameter of circular hole of thin solid barrier is

∆x=10μm=10μm10-6m1μm=10×10-6m

From equations (1) and (2),

m∆vx=h2∆x∆vx=h2m∆x

Substitute 6.63×10-23J.sfor h,9.11×10-31kgfor mand 10×10-6mfor ∆x.

∆vx=6.63×10-23J.s29.11×10-31kg10×10-6m=36m/s

Therefore, the average velocity is zero. So, the range of velocity is from-18m/sto18m/s

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