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The diameter of the nucleus is about 10fm. What is the kinetic energy, in MeV, of a proton with a de Broglie wavelength of10fm ?

Short Answer

Expert verified

Ek=1.3·10-12J=8.2MeV

Step by step solution

01

Given Information

The diameter of the nucleus is about 10fm. proton with a de Broglie wavelength of 10fm

02

Calculation

We can start the solution by determining de Broglie wavelength

λ=hmvv=hmλEk=mv22Ek=mh22m2λ2Ek=h22mλ2Ek=6.63·10-3422·1.67·10-27·10·10-152Ek=1.3·10-12J=8.2MeV

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