Q.24 I FIGURE EX38.24 is an energy-le... [FREE SOLUTION]

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Chapter 38: Q.24 (page 1114)

I FIGURE EX38.24 is an energy-level diagram for a simple atom. What wavelengths, in \mathrm{nm}, appear in the atom's (a) emission spectrum and (b) absorption spectrum?
$n = 3 鉄� E_{3} = 4.00 eV$
$n = 2 - E_{2} = 1.50 eV$
FIGURE EX38.24 n=1-E_{1}=0.00 \mathrm{eV}

Short Answer

Expert verified

a) $位_{21} = 828.26 nm, 位_{31} = 310.6 nm, 位_{32} = 497.36 nm$

b) $位_{12} = 828.26 nm, 位_{13} = 310.6 nm$

Step by step solution

part (a) step 1 : given information

We can start the solution with expression for wavelength from transition

$位 = \frac{h c}{螖 E} 位_{21} = \frac{h c}{E_{2} - E_{1}} (t r a n s i t i o n 2 鈫� 1) 位_{21} = \frac{6.63 路 10^{- 34} 路 3 路 10^{8}}{1.5 路 1.6 路 10^{- 19} - 0} (s u b s t i t u t e) 位_{21} = 828.26 nm 位_{31} = \frac{h c}{E_{3} - E_{1}} (t r a n s i t i o n 3 鈫� 1) 位_{31} = \frac{6.63 路 10^{- 34} 路 3 路 10^{8}}{4 路 1.6 路 10^{- 19} - 0} (s u b s t i t u t e) 位_{31} = 310.6 nm 位_{32} = \frac{h c}{E_{3} - E_{2}} (t r a n s i t i o n 3 鈫� 2) 位_{32} = \frac{6.63 路 10^{- 34} 路 3 路 10^{8}}{4 路 1.6 路 10^{- 19} - 1.5 路 1.6 路 10^{- 19}} (s u b s t i t u t e) 位_{32} = 497.36 nm$

part (b) step 1 : given information

Atom is in the n=1 state, so we have only absorption from $1 鈫� 2$ and $1 鈫� 3$ . Expressions are same, so wavelengths are same.

1 鈫� 2 :

位_{12} = 828.26 nm

$1 鈫� 3 :$ $位_{13} = 310.6 nm$

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91影视

I FIGURE EX38.24 is an energy-level diagram for a simple atom. What wavelengths, in \mathrm{nm}, appear in the atom's (a) emission spectrum and (b) absorption spectrum?
$n = 3 鉄� E_{3} = 4.00 eV$
$n = 2 - E_{2} = 1.50 eV$
FIGURE EX38.24 n=1-E_{1}=0.00 \mathrm{eV}

Short Answer

Step by step solution

part (a) step 1 : given information

part (b) step 1 : given information

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91影视

I FIGURE EX38.24 is an energy-level diagram for a simple atom. What wavelengths, in \mathrm{nm}, appear in the atom's (a) emission spectrum and (b) absorption spectrum?n=3鉄�E3=4.00eVn=2-E2=1.50eVFIGURE EX38.24 n=1-E_{1}=0.00 \mathrm{eV}

Short Answer

Step by step solution

part (a) step 1 : given information

part (b) step 1 : given information

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Physics Textbooks

Electrostatics

Famous Physicists

Magnetism and Electromagnetic Induction

Scientific Method Physics

Wave Optics

Medical Physics

Study anywhere. Anytime. Across all devices.

I FIGURE EX38.24 is an energy-level diagram for a simple atom. What wavelengths, in \mathrm{nm}, appear in the atom's (a) emission spectrum and (b) absorption spectrum?
$n = 3 鉄� E_{3} = 4.00 eV$
$n = 2 - E_{2} = 1.50 eV$
FIGURE EX38.24 n=1-E_{1}=0.00 \mathrm{eV}