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a. What wavelength photon does a hydrogen atom emit in a 200→199transition?

b. What is the difference in the wavelengths emitted in a localid="1650823513478" 199→2transition and a 200→2transition?

Short Answer

Expert verified

(a) In a transition, wavelength photon a hydrogen atom emit is λ200→199=0.362m

(b) The difference in the wave lengths areΔλ=0.368pm

Step by step solution

01

Part (a) Step 1: Given information

The wavelength of hydrogen atom is200→199

02

Part (a) Step 2: Finding emission spectrum wavelength

We can start with an expression for the emission spectrum wavelength.

λn→m=λ01m2−1n2λ200→199=91.18⋅10−911992−12002(200→199transition)λ200→199=0.362m

03

Part (b) Step 1: Given information

The given wavelengths are199→2and200→2

04

Part (b) Step 2: Finding difference between wavelengths

In the same approach, we can figure out 199→2transition and 200→2transition

localid="1651154009746" λ199→2=91.18×10−9122−11992λ200→2=91.18×10−9122−12002Δλ=λ199→2−λ200→2(difference between wavelengths)Δλ=91.18×10−9122−11992−91.18×10−9122−12002(substitute)Δλ=0.368pm

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