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What is the energy, in eV, of (a) a 450 MHz radio-frequency photon, (b) a visible-light photon with a wavelength of 450 nm, and (c) an x-ray photon with a wavelength of 0.045 nm?

Short Answer

Expert verified

a) Energy is equal to 1.86×10-6eV.

b) Energy is equal to 2.76 eV.

c) Energy is equal to 27.6 keV.

Step by step solution

01

Step 1. Given Information is :a) a 450 MHz radio-frequency photon b) a visible-light photon with a wavelength of 450 nmc) an x-ray photon with a wavelength of 0.045 nm 

We need to find out the energy of the given photons.

02

Step 2. Part a) Using expression of Energy of a photon.

E=hfE=(6.63×10-34)(450×106Hz)E=2.98×10-25JE=1.86×10-6eV

03

Step 3. Part b) Using expression of Energy of a photon. 

E=hff=cλE=hcλE=(6.63×10-34)(3×108m/s)450×10-9mE=4.42×10-19JE=2.76eV

04

Step 4. Part c) Using expression of Energy of a photon. 

E=hcλE=(6.63×10-34)(3×108m/s)0.045×10-9mE=4.42×10-15JE=27.6keV

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