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FIGURE P21.60is the pVdiagram of Example 21.2, but now the device is operated in reverse.

a. During which processes is heat transferred into the gas?

b. Is thisQH, heat extracted from a hot reservoir, or QC, heat extracted from a cold reservoir? Explain.

c. Determine the values ofQHandQC.

Hint: The calculations have been done in Example 21.2and do not need to be repeated. Instead, you need to determine which processes now contribute to QHand which to QC.

d. Is the area inside the curve Winor Wout? What is its value?

e. The device is now being operated in a ccw cycle. Is it a refrigerator? Explain.

Short Answer

Expert verified

a. In process 4→3heat transferred into the gas.

b. Heat extracted from cold reservoir.

c. Heat of hot reservoir is 26.33×105J,cold reservoir is 22.28×105J.

d. Area inside the curve is Winand it is counter clockwise.

e. Device is operated in a ccw cycle is not refrigerator.

Step by step solution

01

Explanation (part a)

a.

- 4→3This is a volume-increasing isobaric process (isobaric expansion). The effort done is good since the gas expands.

Also, in the isobaric process, the temperature rises, implying that the thermal energy rises.

According to the first law of thermodynamics, the received heat is positive because both the work done and the change in thermal energy are positiveQ=W+Δ·¡th.

In this process, the heat is transferred to the gas.

02

Explanation (part b)

b.

The heat removed from the cold reservoir isQC.

The gas takes heat only when it reaches its lowest temperature of 300Kat point four (the temperature of the cold reservoir).

And it begins to release heat when it reaches its greatest temperature of 2700Kat point two (the temperature of the hot reservoir) (the temperature of the hot reservoir).

03

Explanation (part c)

c.

Heat is,

QC=Q43+Q32,

QH=Q21+Q14

So,

localid="1650295407041" Q43=7.09×105J,

localid="1650295443209" Q32=15.19×105J,

Q21=-21.27×105J,

localid="1650295457797" Q14=-5.06×105J.

This yields

localid="1650295473714" QC=22.28×105J,andQH=26.33×105J

04

Explanation  (part d)

d.

We take heat from the cold reservoir and transfer it to the hot reservoir in larger amounts.

This is impossible without putting in effort, according to the second rule of thermodynamics, hence this area isWin.

Another criterion is that if a cycle is clockwise (cw), the area isWout, and if it is counterclockwise (ccw), the area is Win.

The cycle in our situation is counterclockwise.

05

Explanation (part e)

e.

This cycle isn't modelled after a refrigerator.

Because there is no colder reservoir thanTC with which the gas can exchange heat.

The gas must reach lower temperatures than TC=300K, which is only possible via adiabatic expansion (no heat transfer).

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Most popular questions from this chapter

The FIGURE shows the Diesel cycle. It is similar to the Otto cycle (see Problem), but there are two important differences. First, the fuel is not admitted until the air is fully compressed at point 2. Because of the high temperature at the end of adiabatic compression, the fuel begins to burn spontaneously. (There are no spark plugs in a diesel engine!) Second, combustion takes place more slowly, with fuel continuing to be injected. This makes the ignition stage a constant-pressure process. The cycle shown, for one cylinder of a diesel engine, has a displacement localid="1650278379201" Vmax-Vminof localid="1650278390412" 1000cm3and a compression ratio localid="1650278397535" r=Vmax/Vmin=21These are typical values for a diesel truck. The engine operates with intake air localid="1650278425123" (γ=1.40)at localid="1650278430754" 25°Cand localid="1650278435051" 1.0atmpressure. The quantity of fuel injected into the cylinder has a heat of combustion of localid="1650278440305" 1000J.

a. Find p, V, and Tat each of the four corners of the cycle. Display your results in a table.

b. What is the network done by the cylinder during one full cycle?

c. What is the thermal efficiency of this engine?

d. What is the power output in kW and horsepower (1hp=746W)of an eight-cylinder diesel engine running at 2400rpm?

What are (a) WoutandQHand (b) the thermal efficiency for the heat engine shown in FIGUREEX21.14?

The first and second laws of thermodynamics are sometimes stated as "You can't win" and "You can't even break even." Do these sayings accurately characterize the laws of thermodynamics as applied to heat engines? Why or why not?

A Carnot heat engine operates between reservoirs at 182°Cand 0°C. If the engine extracts 25Jof energy from the hot reservoir per cycle, how many cycles will it take to lift a 10Kg mass a height of 10m?

FIGURE P21.57shows the cycle for a heat engine that uses a gas having γ=1.25.The initial temperature isT1=300K, and this engine operates at20cycles per second.

a. What is the power output of the engine?

b. What is the engine's thermal efficiency?

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