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72. An electric oscillator is made with a 0.10μFcapacitor and a 1.0mHinductor. The capacitor is initially charged to5.0V . What is the maximum current through the inductor as the circuit oscillates?

Short Answer

Expert verified

The current passing through the circuit is 0.05 A.

Step by step solution

01

Step 1. Given information

The value of inductance, and capacitance

L=(1.0mH)1H1000mH=0.001HC=(0.10μF)1×10−6F1μF=1.0×107F

02

Step 2. Explanation

Equate the potential energy stored in the capacitor is equal to potential energy stored in inductor.

UC=UL12LI2=12CΔV2I=ΔVCLI=(25V)(8.0pF)1×10−12F1pF(20mH)1H1000mHI=5×10−4A

Therefore, the current passing through the circuit is 0.05A

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Most popular questions from this chapter

The L-shaped conductor in FIGUREP30.54 moves at 10m/sacross and touches a stationary L-shaped conductor in a 0.10Tmagnetic field. The two vertices overlap, so that the enclosed area is zero, at t=0s. The conductor has a resistance of 0.010ohms per meter.

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