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A vertical, rectangular loop of copper wire is half in and half out of the horizontal magnetic field in FIGURE (The field is zero beneath the dashed line.) The loop is released and starts to fall. Is there a net magnetic force on the loop? If so, in which direction? Explain

Short Answer

Expert verified

Yes, there is a net upward force.

Step by step solution

01

Introduction

The current-carrying portion of oblong is near a protractor long straight wire that runs parallel to one of the loop's sides. The loop will close if a constant current I is established within the wire. It revolve around an axis perpendicular to the wire

02

Lenz law

In electromagnetism, Lenz's law states that an induced current flows within the reverse direction of the change that caused it. Heinrich Friedrich Emil Lenz (1804–65), a Russian scientist, deduced this law in 1834.

According to the Lenz law,

Because the highest top loop segment traverses the sphere field while the lower loop segment does't (the two side segments produce forces of equal magnitude but in different directions), the net force are going to the upward. It must oppose the gravitational attraction that's generating the flow change.

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Most popular questions from this chapter

FIGURE shows a bar magnet being pushed toward a conducting loop from below, along the axis of the loop.

a. What is the current direction in the loop? Explain.

b. Is there a magnetic force on the loop? If so, in which direction? Explain.

Hint: A current loop is a magnetic dipole.

c. Is there a force on the magnet? If so, in which direction?

The square loop shown inFIGUREP30.53 moves into a 0.80TALCmagnetic field at a constant speed of10m/s.The loop has a resistance of 0.10Ω, and it enters the field at t=0s.

a. Find the induced current in the loop as a function of time. Give your answer as a graph of ii versus tfrom t=0sto t=0.020s.

b. What is the maximum current? What is the position of the loop when the current is maximum?

At , the current in thet=0scircuit in FIGURE EX30.35is I0. At what time is the current 12I0

56. II Your camping buddy has an idea for a light to go inside your CALC tent. He happens to have a powerful (and heavy!) horseshoe magnet that he bought at a surplus store. This magnet creates a0.20T field between two pole tips 10cmapart. His idea is to build the hand-cranked generator shown in FIGURE P30.56. He thinks you can make enough current to fully light a1.0Ωlightbulb rated at 4.0W. That's not super bright, but it should be plenty of light for routine activities in the tent.

a. Find an expression for the induced current as a function of time if you turn the crank at frequency f Assume that the semicircle is at its highest point at t=0s.

b. With what frequency will you have to turn the crank tor the maximum current to fully light the bulb? Is this feasible?

The switch in FIGURE P30.76 has been open for a long time. It is closed at t=0s. What is the current through the 20Ωresistor

a. Immediately after the switch is closed?

b. After the switch has been closed a long time?

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