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What is the direction of the induced current in FIGURE Q30.1

Short Answer

Expert verified

The direction of the induced current is determined as, a counterclockwise current creates the next force , which tends to tends flux inside the loop.

Step by step solution

01

 Step :1 Introduction

The induced current is the current that 's induced in a very conducting loop that's is exposed to a changing magnetic field. An induced electrical phenomenon will flow in such a way that it produces a force field that opposes the sphere change that caused it. The given is that the diagram for the induced current. Lenz's law stated as the cause of the induced current is always in opposition to it. As a result, more effort is completed against the opposing force.

02

Step:2 Induced current 

The induced current will flow in the wrong way. The reelm of the loop reduces because the bar goes higher through the constant-magnetic-field zone, and so the flux through the loop decreases.

Any induced current, according to Lenz's Law, will tend to reverse this drop. Inside the loop, a counterclockwise current creates a better force field , which tends to increase flux.

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Most popular questions from this chapter

A 20cm×20cmsquare loop has a resistance of 0.10Ω. A CALC magnetic field perpendicular to the loop is B=4t-2t2, where Bis in Tesla andtis in seconds. What is the current in the loop at t=0.0s,t=1.0s,andt=2.0s?

FIGURE shows a U-shaped conducting rail that is oriented vertically in a horizontal magnetic field. The rail has no electric resistance and does not move. A slide wire with mass mand resistance Rcan slide up and down without friction while maintaining electrical contact with the rail. The slide wire is released from rest.

a. Show that the slide wire reaches a terminal speed vterm, and find an expression forvterm .

b. Determine the value of vtermif l=20cm,m=10g,R=0.10Ωand B=0.50T

An equilateral triangle 8.0cmon a side is in a 5.0mT uniform magnetic field. The magnetic flux through the triangle is 6.0μWb. What is the angle between the magnetic field and an axis perpendicular to the plane of the triangle?

An 8.0cm×8.0cmsquare loop is halfway into a magnetic CALC field perpendicular to the plane of the loop. The loop's mass is and its resistance is 0.010Ω. A switch is closed at t=0s, causing the magnetic field to increase from0to1.0Tin0.010s .

a. What is the induced current in the square loop?

b. With what speed is the loop "kicked" away from the magnetic field?

Hint: What is the impulse on the loop?

Equation 30.26 is an expression for the induced electric field CALC inside a solenoid(r<R) . Find an expression for the induced electric field outside a solenoid(r>R) in which the magnetic field is changing at the ratedB/dt .

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