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70. II The current through inductance Lis given byI=I0e−t/τ .

CALC a. Find an expression for the potential difference ΔVLacross the inductor.

b. Evaluate ΔVLat t=0,1.0, and 3.0msif L=20mH,I0=50mA, and τ=1.0ms.

Short Answer

Expert verified

Part (a) The potential difference isΔVL=LI0τe−tt

Part (b) Potential difference at different times

time (S)

potential difference

0 s

1000 mV

1 s

370 mV

2 s

140 mV

3 s

50 mV

Step by step solution

01

Part (a)

The expression for current is,

I=I0etr

The expression for the potential difference,ΔVLis

ΔVL=−LdIdtΔVL=−LddtI0ettΔVL=LI0τe−tt……(1)

The potential difference isLI0τe−tt

02

Part (b) 

L=20mH,Ï„=1.0ms andI0=50mA

At,t=0 â¶ÄŠs

ΔVL1=(20mH)(50mA)(1.0ms)e−0=1000mV

At, t=1 â¶ÄŠs

ΔVL2=(20mH)(50mA)(1.0ms)e−1=370mV

At,t=2 â¶ÄŠs

ΔVL3(t=2s)=(20mH)(50mA)(1.0ms)e−2=140mV

At,t=3 â¶ÄŠs

ΔVL=(20mH)(50mA)(1.0ms)e−3=50mV

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