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Chapter 30: Q. 7 (page 869)

What is the magnetic flux through the loop shown in FIGURE EX30.7?

Short Answer

Expert verified

The magnetic flux through the loop,桅m=(abB)Wb

Step by step solution

01

The magnetic flux  

A magnetic flux桅seems to be the magnitude of magnetic field which passes through some kind of ring of area A. If the magnetic field lies straight towards the plane's normal, This magnetic flux was provided by

localid="1648909960209" 桅m=BA 1

02

The area of the loop

Here Bdenotes the magnetic field as well as Adenotes the substring circumference. The magnetic flux is 0 beyond the selected site. The magnetic field mainly passes into such a rectangle, which has 2 faces aand b. The magnetic flux is zero throughout the ring. As a result, the total area is

role="math" localid="1648905895737" A=ab

03

The magnetic flux through the loop

To calculate total magnetic flux, use the formula of A

桅m=BA=B(ab)=(abB)Wb

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Most popular questions from this chapter

A10cm脳10cmsquare loop lies in the xy-plane. The magnetic field in this region of space is B=0.30t谋^+0.50t2k^T, where tis in s. What is the emfinduced in the loop at at=0.5sand bt=1.0s.

85. III A 2.0-cm-diameter solenoid is wrapped with 1000 turns per CALC meter. 0.50 cm from the axis, the strength of an induced electric field is5.0脳10鈭�4V/m . What is the rate dI/dtwith which the current through the solenoid is changing?

Let's look at the details of eddy-current braking. A square CALC loop, lengthlon each side, is shot with velocityv0into a uniform magnetic field localid="1648921142252" B. The field is perpendicular to the plane of the loop. The loop has mass localid="1648921150406" mand resistancelocalid="1648921154874" R,and it enters the field atlocalid="1648921174281" t=0s. Assume that the loop is moving to the right along thelocalid="1648921181007" x-axis and that the field begins atlocalid="1648921198444" x=0m.

a. Find an expression for the loop's velocity as a function of time as it enters the magnetic field. You can ignore gravity, and you can assume that the back edge of the loop has not entered the field.

b. Calculate and draw a graph oflocalid="1648921211473" vover the intervallocalid="1648921223129" 0s鈮�t鈮�0.04sfor the case thatlocalid="1648816410574" width="87">v0=10m/s,localid="1648921234041" l=10cm,localid="1648921244487" m=1.0g,localid="1648921254639" R=0.0010惟,and localid="1648921264943" B=0.10T. The back edge of the loop does not reach the field during this time interval.

71. II An LC circuit is built with a20mHinductor and an 8.0pFcapacitor. The capacitor voltage has its maximum value of25Vat t=0s.

a. How long is it until the capacitor is first fully discharged?

b. What is the inductor current at that time?

At , the current in thet=0scircuit in FIGURE EX30.35is I0. At what time is the current 12I0
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