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Chapter 32: Q. 20 (page 924)

A high-pass filter consists of a 1.59mFcapacitor in series with a 100鈩�resistor. The circuit is driven by an ACsource with a peak voltage of 5.00V.

a. What is the crossover frequency fc?

b. What is VRwhen f=12fc,fc, and 2fc?

Short Answer

Expert verified

(a) Crossover frequency , fc=1000Hz

(b) Value ofVR=3.54V

Step by step solution

01

AC Source

The flow of electrical charge that occasionally reverses direction is understood as electricity (ac).

As mentioned in Induced Electric Fields, an alternating emf generated in an exceedingly very station produces an ac.

An ac circuit is one during which the ac source varies frequently, often sinusoidally.

02

Find Crossover frequency

Given values

C=1.59脳10-6F(farad)

R=100惟(ohm)

蔚o=5.00V(voltage)

we use formula

w=1RC

Derive from the formula,

w=1RC

2蟺fc=1RC

fc=12蟺RC

localid="1650213173701" fc=12蟺脳(100)惟脳1.59脳10-6)F

fc=1000Hz

03

Find value of voltage

VR=蔚oRR2+1w2C2

VR=蔚oRR2+R2C2C2

Substitute the values,

VR=5.00V1.41

VR=3.54V

f=fc鈬�VR'=蔚o2

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