Chapter 32: Q. 39 (page 925)

A series RLC circuit with a $100 惟$ resistor dissipates $80 W$ when attached to a $120 V / 60 H z$ power line. What is the power factor?

Short Answer

Expert verified

The power factor of RLC circuit is $0.556$ .

Step by step solution

Given Information

We are given that the resistor $R = 100 惟$ , dissipating power $P = 80 W$ and the voltage $V = 120 V$ .

We have to find out the power factor of the RLC circuit.

Formula Used

Now, using the formula,

$P = \frac{V^{2}}{R} 脳 P_{f}$ let this be equation 1

where P is power, V is voltage , R is resistor and $P_{f}$ is power factor.

Simplify

Now put the values of all variables in equation 1,

We get $80 = \frac{{(120)}^{2}}{100} P_{f}$

On rearranging,

We get, $P_{f} = \frac{80 脳 100}{{(120)}^{2}}$

On solving,

$P_{f} = 0.556$

The power factor of RLC circuit is $0.556$ .

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91影视

A series RLC circuit with a $100 惟$ resistor dissipates $80 W$ when attached to a $120 V / 60 H z$ power line. What is the power factor?

Short Answer

Step by step solution

Given Information

Formula Used

Simplify

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91影视

A series RLC circuit with a 100惟resistor dissipates 80Wwhen attached to a 120V/60Hzpower line. What is the power factor?

Short Answer

Step by step solution

Given Information

Formula Used

Simplify

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Physics Textbooks

Force

Waves Physics

Fluids

Dynamics

Particle Model of Matter

Turning Points in Physics

Study anywhere. Anytime. Across all devices.

A series RLC circuit with a $100 惟$ resistor dissipates $80 W$ when attached to a $120 V / 60 H z$ power line. What is the power factor?