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Chapter 32: Q. 4 (page 905)

Draw the phasor for the emf 蔚=(170)cos((2蟺脳60hz)t)att=60ms

Short Answer

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Required figure is given below.

Step by step solution

01

Given information

We need to draw phasor diagram of given equation蔚=(170)cos(2蟺脳60Hzt)att=60ms

02

Explanation

We are given an expression for the instantaneous emf by

鈭�=170Vcos2蟺脳60Hzt

We know that the general expression of instantaneous emf

鈭�=鈭�鈭�coswt+蠒

By comparing both equation

胃=2蟺脳60Hzt胃=2蟺脳60Hz60脳10-3s胃=22.62rad胃=216鈭�

Now, we can draw the phasor by rotating counterclockwise 216鈭�from positive x-axis till the instantaneous emf becomes -137.5Vas shown below.

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Most popular questions from this chapter

A series RLC circuit consists of a 50鈩� resistor, a localid="1650177582139" 3.3mH inductor, and a localid="1650177586647" 480nF capacitor. It is connected to an oscillator with a peak voltage of localid="1650177591401" 5.0V. Determine the impedance, the peak current, and the phase angle at frequencies :

(a) localid="1650177630395" 3000Hz(b) localid="1650177635339" 4000Hzand (c) localid="1650177638990" 5000Hz.

a. What is the peak current supplied by the emf in FIGUREP32.45?

b. What is the peak voltage across the 3.0mFcapacitor?

A series RLC circuit with a 100惟resistor dissipates 80Wwhen attached to a 120V/60Hzpower line. What is the power factor?

You鈥檙e the operator of a 15000Vrms, 60HZ electrical substation. When you get to work one day, you see that the station is delivering 6MWof power with a power factor of0.90.

a. What is the rms current leaving the station?

b. How much series capacitance should you add to bring the power factor up to 1.0?

c. How much power will the station then be delivering?

The peak current through an inductor is 10mA. What is the peak current if

a. The emf frequency is doubled?

b. The emf peak voltage is doubled (at the original frequency)
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