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a. What is the peak current supplied by the emf in FIGUREP32.45?

b. What is the peak voltage across the 3.0mFcapacitor?


Short Answer

Expert verified

a. The peak current supplied by the emf in FIGURE P32.45is 25mA

b. The peak voltage across the 3.0mFcapacitor is6.7V

Step by step solution

01

Part(a) Step 1: Given information 

We are given that the frequency 200Hz, localid="1649935325324" ε0=10V, C=3μFand Ceq=2μF

We need to find peak current supplied by the emf in FIGUREP32.45

02

Part(a) Step 2: Simplify 

The peak current can be calculated by I=VXC,We can calculate and by

V=ε0,XC=12Ï€´Ú°ä, now by putting these value we can get ,

I=ε012Ï€´Ú°ä=2Ï€´Ú°äε0

Finally putting all the values in above equation , we get

I=2Ï€´Ú°äε0=25mA

03

Part(b) step 1: Given information 

We are given that frequency 200Hz,ε0=10V,C=3μFand Ceq=2μF

We have to peak voltage in 3.0mFcapacitor.

04

Part(b) Step 2: Simplify 

We can find peak voltage through the given formula ,VC=I×XC

Where , I=2Ï€´Ú°äeqε0,XC=12Ï€´Ú°ä

Putting the values , we get

VC=CeqCε0

Substituting the values ,VC=CeqCε0=23×10=6.7V

VC=I·XCXC=12Ï€´Ú°ä,I=2Ï€´Ú°äeqε0

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