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Chapter 32: Q. 23 (page 924)

The peak current through an inductor is 10mA. What is the peak current if

a. The emf frequency is doubled?

b. The emf peak voltage is doubled (at the original frequency)

Short Answer

Expert verified

(a) Current is 5mA

(b) Current is20mA

Step by step solution

01

Part (a) Step 1: Given information 

We have been given that,

Current through inductor isI0=10mA

02

Part (a) Step 2: Simplify

Let Voltage is V0

And Frequency is f0

And Inductance is L

And Inductive reactance is localid="1649934635236" XL=2蟺蹿0L

Therefore, Current is

I0=V02蟺蹿0LI0=V02蟺蹿0L

Now, Frequency is doubled i.e. f=2f0

Therefore, Current is,

localid="1649935758169" I=V02蟺蹿LI=V02蟺脳2f0LI=I02I=102I=5mA

Hence, Current is 5mA

03

Part (b) Step 1: Given information 

We have been given that,

Current through inductor isI0=10mA

04

Part (b) Step 2: Simplify

Let Voltage isV0

And inductive reactance isXL

Therefore, Current is

I0=V0XL

Now, Voltage isV=2V0

Therefore, Current is,

I=VXLI=2V0XLI=2I0I=2脳10I=20mA

Hence, current is20mA

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