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Chapter 32: Q. 22 - Exercises And Problems (page 924)

A 20mHinductor is connected across an AC generator that produces a peak voltage of 10V. What is the peak current through the inductor if the emf frequency is (a)

Short Answer

Expert verified

(a) Peak current through inductor is 0路79A

(b) Peak current through inductor is0路00079A

Step by step solution

01

Given information

We have given that,

Inductance of conductor is, L=20mH=20脳10-3H

Peak voltage is,V0=10V

02

Part (a) Step 1: Given information

We have given that,

Frequency is,f1=100Hz

03

Part (a) Step 2: Simplify

Let resistance of inductor is, XL

We know that in inductive circuit resistance is given as,

XL=2脳蟺脳f1脳LXL=2脳3路14脳100脳20脳10-3XL=12路57惟

By ohm's law, we know that,

role="math" localid="1649883173982" Current=VoltageV0ResistanceXLCurrent=1012路57Current=0路79A

Hence, Current through inductor is0路79A

04

Part (b) Step 1: Given information 

We have given that,

Frequency is,f2=100kHz=100脳103Hz

05

Part (b) Step 2: Simplify

Let resistance of inductor is,XL

We know that in inductive circuit resistance is given as,

XL=2脳蟺脳f2脳LXL=2脳3路14脳100脳103脳20脳10-3XL=12566惟

By ohm's law, we know that,

Hence, Current through inductor is0.00079

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